Encyclopedia of Crystallographic Prototypes

AFLOW Prototype: A16B2C_cF152_227_eg_c_b-001

This structure previously used the label(s) A16B2C_cF152_227_eg_d_a. Calls to these addresses will be redirected here.

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https://aflow.org/p/WZBC
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Predicted Li$_{2}$MgH$_{16}$ High-T$_{c}$ Superconductor (250 GPa) Structure: A16B2C_cF152_227_eg_c_b-001

Picture of Structure; Click for Big Picture
Prototype H$_{16}$Li$_{2}$Mg
AFLOW prototype label A16B2C_cF152_227_eg_c_b-001
Pearson symbol cF152
Space group number 227
Space group symbol $Fd\overline{3}m$
AFLOW prototype command aflow --proto=A16B2C_cF152_227_eg_c_b-001
--params=$a, \allowbreak x_{3}, \allowbreak x_{4}, \allowbreak z_{4}$

  • This structure was predicted by (Sun, 2019) as a metastable state of Li$_{2}$MgH$_{16}$ at 250 GPa and T = 0 K. If it is possible to construct this compound, or if it becomes stable due to thermodynamic considerations, it is predicted to have a superconducting transition T$_{c}$ between 430 and 473K.
  • The predicted T = 0 K ground state at 300 GPa is a $P\overline{3}m1$ #164 structure with molecular hydrogen.
  • (Sun, 2019) give the Wyckoff positions in setting 1 of space group $Fd\overline{3}m$ #227. We used FINDSYM to shift this to our standard setting 2.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{2}a \,\mathbf{\hat{z}}\\\mathbf{a_{2}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{z}}\\\mathbf{a_{3}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}a \,\mathbf{\hat{y}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $\frac{3}{8} \, \mathbf{a}_{1}+\frac{3}{8} \, \mathbf{a}_{2}+\frac{3}{8} \, \mathbf{a}_{3}$ = $\frac{3}{8}a \,\mathbf{\hat{x}}+\frac{3}{8}a \,\mathbf{\hat{y}}+\frac{3}{8}a \,\mathbf{\hat{z}}$ (8b) Mg I
$\mathbf{B_{2}}$ = $\frac{5}{8} \, \mathbf{a}_{1}+\frac{5}{8} \, \mathbf{a}_{2}+\frac{5}{8} \, \mathbf{a}_{3}$ = $\frac{5}{8}a \,\mathbf{\hat{x}}+\frac{5}{8}a \,\mathbf{\hat{y}}+\frac{5}{8}a \,\mathbf{\hat{z}}$ (8b) Mg I
$\mathbf{B_{3}}$ = $0$ = $0$ (16c) Li I
$\mathbf{B_{4}}$ = $\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{y}}$ (16c) Li I
$\mathbf{B_{5}}$ = $\frac{1}{2} \, \mathbf{a}_{2}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (16c) Li I
$\mathbf{B_{6}}$ = $\frac{1}{2} \, \mathbf{a}_{1}$ = $\frac{1}{4}a \,\mathbf{\hat{y}}+\frac{1}{4}a \,\mathbf{\hat{z}}$ (16c) Li I
$\mathbf{B_{7}}$ = $x_{3} \, \mathbf{a}_{1}+x_{3} \, \mathbf{a}_{2}+x_{3} \, \mathbf{a}_{3}$ = $a x_{3} \,\mathbf{\hat{x}}+a x_{3} \,\mathbf{\hat{y}}+a x_{3} \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{8}}$ = $x_{3} \, \mathbf{a}_{1}+x_{3} \, \mathbf{a}_{2}- \left(3 x_{3} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+a x_{3} \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{9}}$ = $x_{3} \, \mathbf{a}_{1}- \left(3 x_{3} - \frac{1}{2}\right) \, \mathbf{a}_{2}+x_{3} \, \mathbf{a}_{3}$ = $- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+a x_{3} \,\mathbf{\hat{y}}- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{10}}$ = $- \left(3 x_{3} - \frac{1}{2}\right) \, \mathbf{a}_{1}+x_{3} \, \mathbf{a}_{2}+x_{3} \, \mathbf{a}_{3}$ = $a x_{3} \,\mathbf{\hat{x}}- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{y}}- a \left(x_{3} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{11}}$ = $- x_{3} \, \mathbf{a}_{1}- x_{3} \, \mathbf{a}_{2}+\left(3 x_{3} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}- a x_{3} \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{12}}$ = $- x_{3} \, \mathbf{a}_{1}- x_{3} \, \mathbf{a}_{2}- x_{3} \, \mathbf{a}_{3}$ = $- a x_{3} \,\mathbf{\hat{x}}- a x_{3} \,\mathbf{\hat{y}}- a x_{3} \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{13}}$ = $- x_{3} \, \mathbf{a}_{1}+\left(3 x_{3} + \frac{1}{2}\right) \, \mathbf{a}_{2}- x_{3} \, \mathbf{a}_{3}$ = $a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{x}}- a x_{3} \,\mathbf{\hat{y}}+a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{14}}$ = $\left(3 x_{3} + \frac{1}{2}\right) \, \mathbf{a}_{1}- x_{3} \, \mathbf{a}_{2}- x_{3} \, \mathbf{a}_{3}$ = $- a x_{3} \,\mathbf{\hat{x}}+a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+a \left(x_{3} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (32e) H I
$\mathbf{B_{15}}$ = $z_{4} \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $a x_{4} \,\mathbf{\hat{x}}+a x_{4} \,\mathbf{\hat{y}}+a z_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{16}}$ = $z_{4} \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+a z_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{17}}$ = $\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+a x_{4} \,\mathbf{\hat{y}}- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{18}}$ = $- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{1}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $a x_{4} \,\mathbf{\hat{x}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{19}}$ = $\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $a z_{4} \,\mathbf{\hat{x}}+a x_{4} \,\mathbf{\hat{y}}+a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{20}}$ = $- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $a z_{4} \,\mathbf{\hat{x}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{21}}$ = $z_{4} \, \mathbf{a}_{1}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{22}}$ = $z_{4} \, \mathbf{a}_{1}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{2}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+a x_{4} \,\mathbf{\hat{y}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{23}}$ = $z_{4} \, \mathbf{a}_{1}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $a x_{4} \,\mathbf{\hat{x}}+a z_{4} \,\mathbf{\hat{y}}+a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{24}}$ = $z_{4} \, \mathbf{a}_{1}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}+a z_{4} \,\mathbf{\hat{y}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{25}}$ = $- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}+\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $a x_{4} \,\mathbf{\hat{x}}- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{26}}$ = $\left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}- \left(2 x_{4} + z_{4} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{4} - \frac{1}{4}\right) \,\mathbf{\hat{x}}- a \left(z_{4} - \frac{1}{4}\right) \,\mathbf{\hat{y}}+a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{27}}$ = $- z_{4} \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}- a z_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{28}}$ = $- z_{4} \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $- a x_{4} \,\mathbf{\hat{x}}- a x_{4} \,\mathbf{\hat{y}}- a z_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{29}}$ = $- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}- a x_{4} \,\mathbf{\hat{y}}+a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{30}}$ = $\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{1}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $- a x_{4} \,\mathbf{\hat{x}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{31}}$ = $- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}- a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{32}}$ = $\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $- a x_{4} \,\mathbf{\hat{x}}+a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{33}}$ = $- z_{4} \, \mathbf{a}_{1}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $- a x_{4} \,\mathbf{\hat{x}}- a z_{4} \,\mathbf{\hat{y}}- a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{34}}$ = $- z_{4} \, \mathbf{a}_{1}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}- a z_{4} \,\mathbf{\hat{y}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{35}}$ = $- z_{4} \, \mathbf{a}_{1}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{2}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}- a x_{4} \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{36}}$ = $- z_{4} \, \mathbf{a}_{1}+\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{2}- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{3}$ = $a \left(z_{4} + \frac{1}{4}\right) \,\mathbf{\hat{x}}- a x_{4} \,\mathbf{\hat{y}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{37}}$ = $\left(2 x_{4} + z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $- a z_{4} \,\mathbf{\hat{x}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{y}}+a \left(x_{4} + \frac{1}{4}\right) \,\mathbf{\hat{z}}$ (96g) H II
$\mathbf{B_{38}}$ = $- \left(2 x_{4} - z_{4}\right) \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}- z_{4} \, \mathbf{a}_{3}$ = $- a z_{4} \,\mathbf{\hat{x}}- a x_{4} \,\mathbf{\hat{y}}- a x_{4} \,\mathbf{\hat{z}}$ (96g) H II

References

  • Y. Sun, J. Lv, Y. Xie, H. Liu, and Y. Ma, Route to a Superconducting Phase above Room Temperature in Electron-Doped Hydride Compounds under High Pressure, Phys. Rev. Lett. 123, 097001 (2019), doi:10.1103/PhysRevLett.123.097001.

First cited in

  • D. Hicks, M.J. Mehl, M. Esters, C. Oses, O. Levy, G.L.W. Hart, C. Toher, and S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 3, Comp. Mat. Sci. 199, 110450 (2021). (doi=10.1016/j.commatsci.2021.110450)

Geometry files


Prototype Generator

aflow --proto=A16B2C_cF152_227_eg_c_b --params=$a,x_{3},x_{4},z_{4}$

Species:

Running:

Output: