AFLOW Prototype: A2B3C2D2_tI18_139_e_ad_c_e-001
If you are using this page, please cite:
H. Eckert, S. Divilov, M. J. Mehl, D. Hicks, A. C. Zettel, M. Esters. X. Campilongo and S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 4. Submitted to Computational Materials Science.
Links to this page
https://aflow.org/p/JBSJ
or
https://aflow.org/p/A2B3C2D2_tI18_139_e_ad_c_e-001
or
PDF Version
Prototype | As$_{2}$Mn$_{3}$O$_{2}$Sr$_{2}$ |
AFLOW prototype label | A2B3C2D2_tI18_139_e_ad_c_e-001 |
ICSD | 81798 |
Pearson symbol | tI18 |
Space group number | 139 |
Space group symbol | $I4/mmm$ |
AFLOW prototype command |
aflow --proto=A2B3C2D2_tI18_139_e_ad_c_e-001
--params=$a, \allowbreak c/a, \allowbreak z_{4}, \allowbreak z_{5}$ |
La$_{2}$O$_{3}$Fe$_{2}$S$_{2}$, La$_{2}$O$_{3}$Fe$_{2}$Se$_{2}$, Sr$_{2}$(Mn$_{2}$Cu)As$_{2}$O$_{2}$, Sr$_{2}$(MnZn$_{2}$)As$_{2}$O$_{2}$, Sr$_{2}$Mn$_{3}$Sb$_{2}$O$_{2}$
Basis vectors
Lattice coordinates | Cartesian coordinates | Wyckoff position | Atom type | |||
---|---|---|---|---|---|---|
$\mathbf{B_{1}}$ | = | $0$ | = | $0$ | (2a) | Mn I |
$\mathbf{B_{2}}$ | = | $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{y}}$ | (4c) | O I |
$\mathbf{B_{3}}$ | = | $\frac{1}{2} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}$ | (4c) | O I |
$\mathbf{B_{4}}$ | = | $\frac{3}{4} \, \mathbf{a}_{1}+\frac{1}{4} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ | (4d) | Mn II |
$\mathbf{B_{5}}$ | = | $\frac{1}{4} \, \mathbf{a}_{1}+\frac{3}{4} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ | = | $\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ | (4d) | Mn II |
$\mathbf{B_{6}}$ | = | $z_{4} \, \mathbf{a}_{1}+z_{4} \, \mathbf{a}_{2}$ | = | $c z_{4} \,\mathbf{\hat{z}}$ | (4e) | As I |
$\mathbf{B_{7}}$ | = | $- z_{4} \, \mathbf{a}_{1}- z_{4} \, \mathbf{a}_{2}$ | = | $- c z_{4} \,\mathbf{\hat{z}}$ | (4e) | As I |
$\mathbf{B_{8}}$ | = | $z_{5} \, \mathbf{a}_{1}+z_{5} \, \mathbf{a}_{2}$ | = | $c z_{5} \,\mathbf{\hat{z}}$ | (4e) | Sr I |
$\mathbf{B_{9}}$ | = | $- z_{5} \, \mathbf{a}_{1}- z_{5} \, \mathbf{a}_{2}$ | = | $- c z_{5} \,\mathbf{\hat{z}}$ | (4e) | Sr I |